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x^2+0.97x-0.108=0
a = 1; b = 0.97; c = -0.108;
Δ = b2-4ac
Δ = 0.972-4·1·(-0.108)
Δ = 1.3729
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0.97)-\sqrt{1.3729}}{2*1}=\frac{-0.97-\sqrt{1.3729}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0.97)+\sqrt{1.3729}}{2*1}=\frac{-0.97+\sqrt{1.3729}}{2} $
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